From the code snippet you provided, it seems that the conversion from a string to an integer should work correctly. However, the
NumberFormatException
you are encountering suggests that the string you're trying to convert does not represent a valid integer. One potential reason for this error is that the string you're trying to convert contains non-numeric characters, leading to a failed conversion. Double-check the value of the
numberString
variable to ensure that it only contains numeric characters. If it contains any non-numeric characters or whitespace characters, the
Integer.parseInt()
method will throw a
NumberFormatException
. For example, if the
numberString
is "123abc", the conversion will fail because the "abc" part is not recognized as a valid numeric representation. In such cases, you can remove any non-numeric characters from the string before attempting the conversion. Here's an updated version of your code that removes non-numeric characters using regular expressions:
Code:
public class StringToIntConversion { public static void main(String[] args) { String numberString = "123abc"; numberString = numberString.replaceAll("\\D", ""); // Remove non-numeric characters int number = Integer.parseInt(numberString); System.out.println("Converted Integer: " + number); } }
In this code, we use the
replaceAll()
method with the regular expression
\\D
, which matches any character that is not a digit. This call replaces all non-numeric characters in the
numberString
with an empty string, effectively removing them. By cleaning up the string before performing the conversion, you can avoid the
NumberFormatException
caused by non-numeric characters.