From the code snippet you provided, it seems that the conversion from a string to an integer should work correctly. However, the `NumberFormatException` you are encountering suggests that the string you're trying to convert does not represent a valid integer.
One potential reason for this error is that the string you're trying to convert contains non-numeric characters, leading to a failed conversion. Double-check the value of the `numberString` variable to ensure that it only contains numeric characters. If it contains any non-numeric characters or whitespace characters, the `Integer.parseInt()` method will throw a `NumberFormatException`.
For example, if the `numberString` is "123abc", the conversion will fail because the "abc" part is not recognized as a valid numeric representation. In such cases, you can remove any non-numeric characters from the string before attempting the conversion.
Here's an updated version of your code that removes non-numeric characters using regular expressions:
```java
public class StringToIntConversion {
public static void main(String[] args) {
String numberString = "123abc";
numberString = numberString.replaceAll("\\D", ""); // Remove non-numeric characters
int number = Integer.parseInt(numberString);
System.out.println("Converted Integer: " + number);
}
}
```
In this code, we use the `replaceAll()` method with the regular expression `\\D`, which matches any character that is not a digit. This call replaces all non-numeric characters in the `numberString` with an empty string, effectively removing them.
By cleaning up the string before performing the conversion, you can avoid the `NumberFormatException` caused by non-numeric characters.