def LIS(A):
n = len(A)
lis = [1]*n
for i in range (1 , n):
for j in range(0 , i):
if A[i] > A[j] and lis[i]< lis[j] + 1 :
lis[i] = lis[j]+1
maximum = 0
for i in range(n):
maximum = max(maximum , lis[i])
return maximum
lis
of the same length as the input array A
, where lis[i]
represents the length of the LIS ending at index i
. 2. Dynamic Programming Iteration: It then iterates through each element of the input array A
. For each element...lis
of the same length as the input array A
, where lis[i]
represents the length of the LIS ending at index i
. 2. Dynamic Programming Iteration: It then iterates through each element of the input array A
. For each element at index i
, it loops through all elements before i
(from 0 to i
) to check if the current element can be added to form a longer increasing subsequence. 3. Updating lis
Array: If the current element A[i]
is greater than the element at index j
, and adding the current element A[i]
to the LIS ending at j
would increase the length, then the LIS ending at i
is updated to be one more than the LIS ending at j
. 4. Finding Maximum Length: Finally, the code finds the maximum value in the lis
array, which represents the length of the overall longest increasing subsequence. If you are still facing issues with the code, it might be helpful to run the code on some test cases and print intermediate results to understand how the dynamic programming algorithm works step by step. Additionally, you can share any specific input examples where you are encountering unexpected output for further assistance.