F4RR4R
New Member
- Joined
- Mar 3, 2009
- Messages
- 4
- Thread Author
- #1
Windows 7 includes its own pretty little recovery partition, which uses a non-standard format (UGGH!). I'd like to remove it from my laptop multiboot system. Anyone know if this will cause problems? I use GRUB as my bootloader.
The tail end of my grub file looks like this:
title Windows 7
root (hd0,0)
savedefault
makeactive
chainloader +1
... What i'm worried about is that as the recovery partition is hd0,0 and the operating system itself is located on hd0,1 ... So it looks like the boot process actively relies on the recovery partition.
Update: Just modified GRUB's entry for windows 7 to point at the operating system partition rather than the recovery partition - it generates the error "BOOTMGR Not Found" and won't boot. Why in the world did microsoft put the bootmgr for Windows 7 on a separate partition!? Anyone know a workaround?
The tail end of my grub file looks like this:
title Windows 7
root (hd0,0)
savedefault
makeactive
chainloader +1
... What i'm worried about is that as the recovery partition is hd0,0 and the operating system itself is located on hd0,1 ... So it looks like the boot process actively relies on the recovery partition.
Update: Just modified GRUB's entry for windows 7 to point at the operating system partition rather than the recovery partition - it generates the error "BOOTMGR Not Found" and won't boot. Why in the world did microsoft put the bootmgr for Windows 7 on a separate partition!? Anyone know a workaround?